Two charged particles of equal magnitude
(+Q and +Q) are fixed at opposite corners of a square that lies in a plane (see figure below). A test charge −q is placed at a third corner. If F is the magnitude of the force on the test charge due to only one of the other charges,what is the magnitude of the net force acting on the test charge due to both of these
charges?
1. Fnet = 2F/√3
2. Fnet = √2F
3. Fnet = 2F/3
4. Fnet = F
5. Fnet = 2F
6. Fnet = F/√3
7. Fnet = F/√2
8. Fnet = 3F/2
9. Fnet = 3F
10. Fnet = 0
1 answer
The answer is 2. Fnet=Sqrt of 2 F
3 answers