F = constant / d^2
3 F = constant /x^2
F = c/(8.5^2)
3 F = 3c/(8.5^2) = c/x^2
3 x^2 = 8.5^2
x = 8.5/sqrt(3)
Two charged particles are 8.5cm apart .They moved and the force on each of them is found to be tripled .How far apart are they now
2 answers
electric field strength follows the inverse square law
f d^2 = (3f) D^2
D^2 = d^2 / 3
D = 8.5 / √3
f d^2 = (3f) D^2
D^2 = d^2 / 3
D = 8.5 / √3