F1 = constant/d^2
F2 = same constant/ (d/3)^2 = constant *9/d^2
F2/F1 = 9
so nine times the original force if 1/3 of original seperation
Two charged bodies exert a force of 0.390 N on each other. If they are moved so that they are one-third as far apart, what force is exerted?
is it .390 times 3??
1 answer
1 answer