Two cars are traveling on the same highway. The first car is traveling at an average rate of 44mi/h. The second car leaves an hour late traveling at an average rate of 55mi/h. How long will the cars have traveled when the second car catches up with the first car?

Answer 1

key concept: both would have covered the same distance

let time of first car until catchup be t hrs
let time of 2nd car until they meet be t-1 hrs

55(t-1) = 44t
55t - 55 = 44t
11t = 55
t = 5
distance = 5(44) or 4(55), same thing,
= 220 miles

Answer 2

Thank You