when the distance z between the cars is 18 km, each is 18/√2 = 9√2 km from the marker.
Since z^2 = a^2+b^2,
z dz/dt = a da/dt + b db/dt
18(-19) = 9√2(-16) + 9√2 db/dt
b = 16-9√2 ≈ 10.87 km/hr
A will clearly get there first
Two cars are racing with a constant speed towards a finish Marker. Car a is moving from South at 16km/h and car But is moving from east. When equidistant from marker the cars are 18km apart and the distance between them is decreasing at the rate of 19km/h which car will win the race and explain your answer
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