a + b = 273 / 3 mph = 91 mph
a - b = 7 mph
adding equations (eliminating b)
... 2 a = 98 mph
Two cars are 273 mi apart and traveling towards each other on the same road. THey meet in 3 hr. One car is traveling 7 mph faster than the other. What is the speed of each car?
2 answers
speed of slower car --- x mph
speed of faster car ---- x+7 mph
distance of slower car = 3x
distance of faster car = 3(x+7)
3x + 3(x+7) = 273
carry on ...
speed of faster car ---- x+7 mph
distance of slower car = 3x
distance of faster car = 3(x+7)
3x + 3(x+7) = 273
carry on ...