Two cars, 127 miles apart, start moving towards each other at the same time. One is moving 3 times as fast as the other. If they meet 1.5 hrs later, find the average speed of the slower car in miles per hour?

Answer 1

slower car moves 127/4 miles in 1.5 hrs

(127/4 mi) / 1.5hr = 21.17 mi/hr

Answer 2

Sorry, how did you get that? :(

Answer 3

v1•t+v2•t=s
v1=v, v2=3v,
v•t+3v•t=4•v•t=s
v=s/4•t =127/4•1.5 =21.17 mph

Answer 4

Oh! I understand now, thanks so much to both :)