since there is no restriction on the first card, p(pair) = p(2nd card is same value as 1st card)
p(pair) = 1 * 3/51 = 1/17
p(no pair) = 16/17
Two cards are selected at random without replacement from a well-shuffled deck of 52 playing cards. Find the probability of the given event. A pair is not drawn.
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