Two capacitors C1 = 7.00 µF and C2 = 11.0 µF are connected in series to a 9.00 V battery.

Question

(a) Find the equivalent capacitance of the combination.
µF

(b) Find the potential difference across each capacitor.

(c) Find the charge on each capacitor.

Answer 1

a. Ct = C1*C2?(C1+C2)
Ct = 7*11/(7+11) = 4.28 uF. = Total capacitance.

b. Qt = Ct*V = 4.28 * 9 = 38.5 uC=Q1=Q2

Q1 = C1*V1 = 38.5
7 * V1 = 38.5
V1 = 5.5 Volts.

C2 * V2 = Qt
V2 = 38.5/11 = 3.5 Volts.

c. Q1 = Q2 = Qt = 38.5 uC.