=> First, we calculate the net charge stored in the initial circuit.
=> Q stored in C1 = CV = 2 x 120 = 240 micro Coul.
=> Q stored in C2 = CV = 6 x 120 = 720 micro Coul.
That gives us a total charge of 960 micro Coul.
Try using the following hints now to get at the answer yourself:
- In the new circuit, both capacitors will be considered to be in parallel
- The net charge will remain 960 micro Coul. due to conservation of charge
I'd be happy to help further if you can't get to the answer, but do attempt it yourself first!
Two capacitors A and B having capcitance 2micro farad and 6 micro farad are charged separately to same potential of 120 volt.Now pisitive plate of A is connected to negative plate of B and negative plate of A is connected to positve plate of B. Find final charge on each capacitor.
2 answers
Just to be clear, the point I was making by 'will be in parallel' is that they will have a common potential difference (V). So you have the values of C, a common value for V, and the total value of Q. Can you recall a certain equation which includes C, V, and Q?