Two bullets have masses of 4.6 g and 11 g,

Question

respectively. Each is fired with a speed of 41.0
m/s.
a) What is the kinetic energy of the first
bullet?
Answer in units of J.

Answer 1

a) Kinetic Energy = (1/2)*M1*V^2

M1 = 0.0046 kg

Information about the second bullet is not needed to answer this question.

Answer 2

KE= 0.0046 x 41 x 41 x 0.5

= 3.8663 Joules