Two buildings of equal height are 850 feet apart. An observer on the street between the buildings measures the angles of elevation to the tops of the buildings as 29° and 40°. How high, to the nearest foot, are the buildings?

Question

Two buildings of equal height are 850 feet apart. An observer on the street between the buildings measures the angles of elevation to the tops of the buildings as 29° and 40°. How​ high, to the nearest​ foot, are the​ buildings?

I don't know how to set this up

Anonymous · Answer

x and 850 -x tan 29 = h/x so x = 1.804 h tan 40 = h/(850-x)= .8391 h = (850 -1.804h)(.8391)

Two buildings of equal height are 850 feet apart. An observer on the street between the buildings measures the angles of elevation to the tops of the buildings as 29° and 40°. How​ high, to the nearest​ foot, are the​ buildings?

Two buildings of equal height are 850 feet apart. An observer on the street between the buildings measures the angles of elevation to the tops of the buildings as 29° and 40°. How high, to the nearest foot, are the buildings?