m=mass of partly filled bucket=6.3kg
M=Mass of filled bucket=10.3kg
ma=T-63
Ma=103-T
ma+63=103-Ma
a=(103-63)/(M+m)=2.41
Plug a back into one of the original equations we solve for T:
T=ma+63=(6.3)(2.41)+63=78.2
2 years ago
Two buckets of sand hang from opposite ends of a rope that passes over an ideal pulley. One bucket is full and weighs 110 N; the other bucket is only partly filled and weighs 50 N .
Initially, you hold onto the lighter bucket to keep it from moving. What is the tension in the rope?
You release the lighter bucket and the heavier one descends. What is the tension in the rope now?
Eventually the heavier bucket lands and the two buckets come to rest. What is the tension in the rope now?
Can anyone help me i've been doing this all night?
1 answer
1 answer