two boys start running straight towards each other from two points that are 100m apart. one runs with a speed of 5m/s, while other moves at 7m/s.how close are they to the slower one's starting point when they meet?

Answer 1

The distance between them is reduced at a rate 12 m/s, and they meet after 100/12 = 8.333 s. At that time, the slower runner is
5 * 8.333 = 41.67 m from his starting point. As a fraction, that is 125/3 meters.