Two boxes are connected by a weightless cord running over a very light frictionless pulley as shown in the figure. Box A, of mass 8.0 kg, is initially at rest on the top of the table. The coefficient of kinetic friction between box A and the table is 0.10. Box B has a mass of 15.0 kg, and the system begins to move just after it is released. What is the tension in the cord?

asked by qais

8 years ago

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1 answer

T-F=m1a
m2g-T=m2a
a=(m2g-F)/(m1+m2)=6.06
T=m1a+F=56.3N
Tension is 56.3N

answered by Bruv

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Question

Two boxes are connected by a weightless cord running over a very light frictionless pulley as shown in the figure. Box A, of mass 8.0 kg, is initially at rest on the top of the table. The coefficient of kinetic friction between box A and the table is 0.10. Box B has a mass of 15.0 kg, and the system begins to move just after it is released. What is the tension in the cord?

1 answer

T-F=m1a
m2g-T=m2a
a=(m2g-F)/(m1+m2)=6.06
T=m1a+F=56.3N
Tension is 56.3N

Ask a New Question or answer this question.

Bruv · Answer

T-F=m1a m2g-T=m2a a=(m2g-F)/(m1+m2)=6.06 T=m1a+F=56.3N Tension is 56.3N