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Two bowling balls of different masses collide while accelerating at 1.875 m/s2%0D%0A2%0D%0A. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)%0D%0AResponses%0D%0A%0D%0A8.875 N to the right%0D%0A8.875 N to the right%0D%0A%0D%0A3.73 N to the right%0D%0A3.73 N to the right%0D%0A%0D%0A13.125 N to the right%0D%0A13.125 N to the right%0D%0A%0D%0A7.5 N to the left

1 answer

To determine the force that the 7 kg bowling ball exerts on the 4 kg bowling ball during their collision, we can use Newton's second law of motion, \( F = ma \).

  1. Calculate the force exerted by the first bowling ball (7 kg): \[ F_1 = m_1 \cdot a = 7 , \text{kg} \cdot 1.875 , \text{m/s}^2 = 13.125 , \text{N} \]

This means the 7 kg bowling ball exerts a force of 13.125 N.

  1. Direction of the Force:
    • The 7 kg ball is rolling to the right, so the force it exerts on the 4 kg ball is also to the right.

Therefore, the correct response is: 13.125 N to the right.