a) friction force=mu*(2*2.4)g
b) Friction force=6.8 if constant velocity, solve for mu.
Two blocks (one on top of the other), each of mass m = 2.4 kg, are pushed along the horizontal surface of a table by a horizontal force P of magnitude 6.8 N, directed to the right. The blocks move together to the right at constant velocity.
(a) Find the frictional force exerted on the lower block by the table.
(b) Find the coefficient of kinetic friction between the surface of the block and the table.
2 answers
what exactly does mu stand for?