Two blocks of mass 3kg and 2 kg are jointed with a massless and inextensible string. If breaking tension of string is 10N find the maximum horizontal force with two blocks can be pulled on the surface.
2 answers
50/3N
a1 is 10/3 m/s square
a2 is 10/2=5 m/s square
Now
F =(2+3)*5=25 N
a2 is 10/2=5 m/s square
Now
F =(2+3)*5=25 N
1 answer