since you give no information as to their directions, I will assume they are traveling in opposite directions.
So, if the .1kg mass is moving in the + direction, we have
0.1*0.4 - 0.2*1.0 = (0.1+0.2)v
v = -8/15
Two blocks of mass 0.1 kg and 0.2 kg approach each other on a frictionless
surface at velocities of 0.4 and 1 m/s respectively. If the blocks collide and remain
together, calculate their joint velocity after the collision.
1 answer
1 answer