Let mass of hanging block be M
Since in equilibrium the hanging mass MG = Tension in the wire
Similarly along the incline Tension in the wire = 6.7 * g * sin 42 (Component of force along the incline)
So equation both the equations:
M*g = 6.7 * g * sin(42)
M = 6.7*sin(42)
So M = 6.7*sin(42)
two blocks are connected by a string. the smooth incline surface makes an angle of 42 degrees with the horizontal, andthe block on the incline has a mass of 6.7 kg. find the mass of the hanging block that will cause the system to be in equilibrium. (the pully is assumed to be ideal.)
3 answers
Two blocks are connected by a string, as shown in the figure. The system is in equilibrium. The inclined
6.14