Two blocks are connected by a lightweight, flexible cord that passes over a frictionless pulley. If m1 = 3.8 kg and m2 = 9.2 kg, and block 2 is initially at rest 140 cm above the floor, how long does it take block 2 to reach the floor?

Answer 1

Acceleration a = (m2 -m1)/(m2 +m1) * g
Solve for t:

(a/2)*t^2 = 0.140 meters