Use the kinematic equation v^2=u^2+2ax
When you find the acceleration multiply it by the mass of the block on the table
Two blocks are arranged at the ends of a massless string as shown in the figure. The system starts from rest. When the 3.21 kg mass has fallen through 0.4 m, its downward speed is 1.27 m/s. The acceleration of gravity is 9.8 m/s2 .
3.21 kg (box hanging from table)
4.96 kg (box on table)
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a
What is the frictional force between the 4.96 kg mass and the table?
Answer in units of N.
1 answer
1 answer