Two balls, one of gold with a mass of 100 kg and one of wood with a mass of 1 kg, are suspended 1 meter apart. What is the attractive force, in newtons, of

a. the gold ball acting on the wooden ball?
b. the wooden ball acting on the gold ball?

2 answers

a,b both forces are equal and opposite.

a. force=GMm/distance^2
I solve it, but i don't know the sign of each one of them .. can you help me in this part please ..

F = (G.m1.m2) / (r2)
F = (6.673 x 10-11 x 100 x 1) / (12)
F = 6.673 x 10-9 N