ball1: d=1/2 g t^2
ball2: d=1/2 g (t/2)^2
difference in distance
ball1-ball2=1/2 gt^2 (1-1/4)=
ball1(3/4)
ball2 went 1/4 as far as ball1.
The difference in distance is 3/4 the distance ball1 went.
I am not certain your teacher really meant "difference'.
two balls are dropped in a vacuum. if one is caught in half the time as the other what is the difference in distance the balls traveled?
a.1/4*t
b.1/4*t^2
c.1/2*t^2
d.15/3*t
e.15/4*t^2
I believe it is b. but i'm not 100% sure.
1 answer