momentum x = m Via
momentum y = 0
after
m Via = m Va cos 30 + m Vb cos 45
0 = m Va sin 30 - m Vb sin 45
Two asteroids
of equal mass collide as shown in the
figure. After the collision, asteroid A’s
trajectory is deflected by 30 degrees
from its initial motion. Asteroid B is
initially at rest and its final velocity
makes a 45 degree angle with respect
to the initial trajectory of asteroid A.
14 answers
a) What is the final speed of each asteroid? Express your answer as a vector.
b) What fraction of asteroid A’s initial kinetic energy dissipates during the collision?
b) What fraction of asteroid A’s initial kinetic energy dissipates during the collision?
You have to use the two equations I derived to get Va and Vb in terms of Via, the initial speed of A
then you can do the x and y components
then you can do the x and y components
The initial velocity before A hit B was 40 m/s
I still don't understand what you are trying to say.
Vb = Va sin 30/sin 45
then
Via = Va cos 30 + (Va sin 30/sin 45)cos 45
then
Via = Va cos 30 + (Va sin 30/sin 45)cos 45
so Via = 40
You did not say that
use it
You did not say that
use it
so you can solve for Va, the speed of A after
then for Vb the speed of B after
then for Vb the speed of B after
what is Va? That is what is confusing me the most
Va is the speed of A after collision
how would i do part b?
once you have Va and Vb
Ke before = (1/2) m Via^2
Ke after = (1/2) m Va^2 + (1/2) m Vb^2
note m cancels everywhere in this problem
I think you can do the lost over the initial
Ke before = (1/2) m Via^2
Ke after = (1/2) m Va^2 + (1/2) m Vb^2
note m cancels everywhere in this problem
I think you can do the lost over the initial
Thank you so much
You are welcome.