Two ants race across a table 70 cm long. One travels at 5.7 cm/s and the other at 3.99999 cm/s. When the first one crosses the finish line,how far behind is the second one? Answer in units of cm

Answer 1

Are we to assume that they started at the same time?

3.9999 cm/s might as well be called 4.0 cm/s, since there are only two significant figures for other numbers.

Answer 2

t1 = 70cm / 5.7cm/s = 12.88s = the 1st
ants' time.

d2=4cm/s * 12.88s = 49.12cm = Distance the 2nd ant ran during the 12.88s.

d = 70 - 49.12 = 20.88cm = Distance behind.