Two angles of a triangle are equal and the third angle is greater than each one of them by 18 degree.Find the angles.

Answer 1

A1 = A2
Eq: A1 + A2 + A3 = 180o
A1 + A2 + (A1+18) = 180
Replace A2 with A1:
A1 + A1 + (A1+18) = 180
3A1 + 18 = 180
3A1 = 180-18 = 162
A1 = A2 = 54o
A3 = A1 + 18 = 54 + 18 = 72o.

Answer 2

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