Two angles are supplementary with measures m∠ACB=4x° and m∠BCD=(6x+50)°. What is the measure of ∠ACB?

m∠ACB=__°

1 answer

Two angles are supplementary when their measures add up to 180°. Given the angles:

\[ m∠ACB = 4x° \quad \text{and} \quad m∠BCD = (6x + 50)° \]

Since these two angles are supplementary, we have:

\[ m∠ACB + m∠BCD = 180° \]

Substituting the expressions for the angles:

\[ 4x + (6x + 50) = 180 \]

Now, combine like terms:

\[ 4x + 6x + 50 = 180 \]

Which simplifies to:

\[ 10x + 50 = 180 \]

Next, subtract 50 from both sides:

\[ 10x = 130 \]

Now, divide by 10:

\[ x = 13 \]

Now that we have the value of \( x \), we can find \( m∠ACB \):

\[ m∠ACB = 4x = 4(13) = 52° \]

Thus, the measure of \( ∠ACB \) is:

\[ \boxed{52°} \]