Two angles are supplementary with measure m<ACB =4X and m<BCD=(6X+50). What is the measure of <ACB?

Answer 1

Since the two angles are supplementary, their measures add up to 180 degrees.

Therefore, we have the equation:

4X + 6X + 50 = 180

Combining like terms, we get:

10X + 50 = 180

Subtracting 50 from both sides, we have:

10X + 50 - 50 = 180 - 50

Simplifying, we get:

10X = 130

Dividing both sides by 10, we find:

X = 13

Now we can substitute this value of X into the measure of angle ACB:

m<ACB = 4X = 4(13) = <<4*13=52>>52

Therefore, the measure of angle ACB is 52 degrees.