say
Q = 300 i + 0 j
P = 0 i +300 j
then
P-Q= -300i + 300 j
|P-Q| = magnitude of relative velocity = 300 sqrt 2
tan angle = -1
angle = 45 degrees (P falling behind Q in x)
Two air crafts p and q are flying at the same speed 300 m/s .the direction along which p is flying is at right angle to the direction along which q is flying then find the magnitide of velocity of p relative to q
2 answers
Pq=√Vp^+Vq^. Pq=√300^+300^=424.3