Two 95.0 W (120 \rm V) lightbulbs are wired in series, then the combination is connected to a 120 V supply How much power is dissipated by each bulb?
2 answers
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Figure the resistance of each bulb.
Power= V^2/R
R= 120^2/95
Now that two are in series
power total= V^2/2R= 95/2
power each= 95/4 watts.
Power= V^2/R
R= 120^2/95
Now that two are in series
power total= V^2/2R= 95/2
power each= 95/4 watts.
2 answers