the gravitational constant G =6.67•10⁻¹¹ N•m²/kg²,
PE₁=G•m₁•m₂/R₁
PE₂=G•m₁•m₂/R₂
E=ΔPE= PE₁-PE₂=
=G•m₁•m₂/R₁-G•m₁•m₂/R₂=
=G•m₁•m₂(1/ R₁- 1/R₂)= …
R₁=0.26 m
R₂= 1 m, 10 m
Two 0.61 kg basketballs, each with a radius of 13 cm, are just touching. How much energy is required to change the separation between the centers of the basketballs to the following (a)1 meter
(b) 10 meters
1 answer
0 answers