To find the new diagonal measurement, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse (diagonal) is equal to the sum of the squares of the other two sides.
For the first question (TV is 5" wider and 3" higher):
Let's first find the length of the diagonal using the original measurements of the TV:
Height = 27"
Width = 48"
Using the Pythagorean theorem:
Diagonal^2 = Height^2 + Width^2
Diagonal^2 = 27^2 + 48^2
Diagonal^2 = 729 + 2304
Diagonal^2 = 3033
Diagonal ≈ √3033
Diagonal ≈ 55.09"
Now, let's find the new diagonal measurement when the TV is 5" wider and 3" higher:
New Height = 27" + 3" = 30"
New Width = 48" + 5" = 53"
Using the Pythagorean theorem again:
New Diagonal^2 = New Height^2 + New Width^2
New Diagonal^2 = 30^2 + 53^2
New Diagonal^2 = 900 + 2809
New Diagonal^2 = 3709
New Diagonal ≈ √3709
New Diagonal ≈ 60.92"
For the second question (TV is 3" wider and 5" higher):
New Height = 27" + 5" = 32"
New Width = 48" + 3" = 51"
Using the Pythagorean theorem:
New Diagonal^2 = New Height^2 + New Width^2
New Diagonal^2 = 32^2 + 51^2
New Diagonal^2 = 1024 + 2601
New Diagonal^2 = 3625
New Diagonal ≈ √3625
New Diagonal ≈ 60.21"
The new diagonal measurements are different in both cases. This is because changing the width and height by different amounts results in different lengths of the diagonal.
TV Size (Diagonal)| Height | Width
32" | 16" |
| 34" | 61"
60" | 30" |
| 20" | 35"
52" | | 45"
Task 2 (6 pts): If a TV has the following dimensions 48” wide, 27” height, and 55” diagonal. Respond to the following questions.
If the TV is 5” wider and 3” higher, what is the new diagonal measurement? (Show work)
If the TV is 3” wider and 5” higher, what is the new diagonal measurement? (Show work)
Depending on the previous responses, why are the diagonal measurements the same or different?
3 answers
are you sure?
I apologize for the confusion in my previous response. Let's calculate the new diagonal measurements correctly.
For the first question (TV is 5" wider and 3" higher):
New Height = 27" + 3" = 30"
New Width = 48" + 5" = 53"
Using the Pythagorean theorem:
New Diagonal^2 = New Height^2 + New Width^2
New Diagonal^2 = 30^2 + 53^2
New Diagonal^2 = 900 + 2809
New Diagonal^2 = 3709
New Diagonal ≈ √3709
New Diagonal ≈ 60.92"
For the second question (TV is 3" wider and 5" higher):
New Height = 27" + 5" = 32"
New Width = 48" + 3" = 51"
Using the Pythagorean theorem:
New Diagonal^2 = New Height^2 + New Width^2
New Diagonal^2 = 32^2 + 51^2
New Diagonal^2 = 1024 + 2601
New Diagonal^2 = 3625
New Diagonal ≈ √3625
New Diagonal ≈ 60.21"
I apologize for the incorrect answer in my previous response. Indeed, both new diagonal measurements are different in the given scenarios.
For the first question (TV is 5" wider and 3" higher):
New Height = 27" + 3" = 30"
New Width = 48" + 5" = 53"
Using the Pythagorean theorem:
New Diagonal^2 = New Height^2 + New Width^2
New Diagonal^2 = 30^2 + 53^2
New Diagonal^2 = 900 + 2809
New Diagonal^2 = 3709
New Diagonal ≈ √3709
New Diagonal ≈ 60.92"
For the second question (TV is 3" wider and 5" higher):
New Height = 27" + 5" = 32"
New Width = 48" + 3" = 51"
Using the Pythagorean theorem:
New Diagonal^2 = New Height^2 + New Width^2
New Diagonal^2 = 32^2 + 51^2
New Diagonal^2 = 1024 + 2601
New Diagonal^2 = 3625
New Diagonal ≈ √3625
New Diagonal ≈ 60.21"
I apologize for the incorrect answer in my previous response. Indeed, both new diagonal measurements are different in the given scenarios.
1 answer