n ≥ 2
looks like you're starting at 18, and adding 6 to each consecutive term
An = 6 (n + 2)
Turn the recursive function into its equivalent explicit function:
f(1) = 18;
f(n) = f(n - 1) + 6;
n is be greater than or equal to 2*
How would I solve this? Any help is appreciated! Thanks!
*The symbol for that is the > with a line under it, I couldn't paste that in jiskha.
4 answers
Yes, n ≥ 2, thank you!
So the answer that was given to me was:
f(n) 12 + 6n; n ≥ 1
So do I just plug in the numbers for An = 6(n + 2) to get there? Sorry, I'm having a bit of trouble understanding it... I'm just unsure of how they came up with that answer.
So the answer that was given to me was:
f(n) 12 + 6n; n ≥ 1
So do I just plug in the numbers for An = 6(n + 2) to get there? Sorry, I'm having a bit of trouble understanding it... I'm just unsure of how they came up with that answer.
An becomes f(n) ... distributing the 6 ... 6n + 12
f(n) = 6 n + 12
f(n) = 6 n + 12
Oh wow! It was so simple I couldn't even see it! I guess I overthought it.... Thank you so much for your help!