The vertical velocity component starts out at 22*sin50 = 16.85 m/s
The horizontal velocity component remains 22*cos50 = 14.14
The time to reach the goal post is
T = 45/14.14 = 3.18 s
The height of the ball at that time is
Y = 16.85 T - (g/2)*T^2
= 53.6 - 49.6 = 4.0 m
Field Goal!
trying to win the superbowl, a placekicker attempts a field goal from 45 m away. when kicked, the ball leaves the ground with a speed of 22m/s at an angle of 50 degrees above the horizontal. what can you say about the ball when it reaches the crossbar that is 3.0m above the ground?
2 answers
so does the ball clear by 1 m or does the ball not clear the crossbar and misses it by 1 m.