Asked by charlie
trying to win the superbowl, a placekicker attempts a field goal from 45 m away. when kicked, the ball leaves the ground with a speed of 22m/s at an angle of 50 degrees above the horizontal. what can you say about the ball when it reaches the crossbar that is 3.0m above the ground?
Answers
Answered by
drwls
The vertical velocity component starts out at 22*sin50 = 16.85 m/s
The horizontal velocity component remains 22*cos50 = 14.14
The time to reach the goal post is
T = 45/14.14 = 3.18 s
The height of the ball at that time is
Y = 16.85 T - (g/2)*T^2
= 53.6 - 49.6 = 4.0 m
Field Goal!
The horizontal velocity component remains 22*cos50 = 14.14
The time to reach the goal post is
T = 45/14.14 = 3.18 s
The height of the ball at that time is
Y = 16.85 T - (g/2)*T^2
= 53.6 - 49.6 = 4.0 m
Field Goal!
Answered by
charlie
so does the ball clear by 1 m or does the ball not clear the crossbar and misses it by 1 m.
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