π/2 > 1 so it diverges
3^n/(-2)^n = (-1)^n * (3/2)^n and 3/2 > 1 so it diverges.
Recall the error bound on alternating series.
Trying to review for the exam. Can someone please help me with this series questions. Thank you
Use geometric series test to determine whether converges or diverges if it converges find the sum
∞
∑. (π/2)^n
n=1
∞
∑. 3^n/(-2)^n
n=2
2 answers
So if it's greater than one it diverges and if its less than one it converges.