2-bromo-4-phenylpentane
will have the bromine atom on the 2nd carbon (hence 2-bromo) and the ph on the 4th carbon (4-phenyl)
hence
CH3CHBrCH2CH(ph)CH3
note that this molecule has two chiral carbon atoms and so there are four possible structures.
Trying to figure out how to draw the structure 2-bromo-4-phenylpentane
I thought it was a five carbon strong with the ring on the second C and a Br on the 4th - but that's not correct (or not completely correct) What am I doing wrong?
2 answers
I had the Br on the second due to the 2-bromo, and the ring on the 4th, but it was marked wrong so then I thought perhaps it should have been flipped right to left - which reading left to right would have put the Br on the 4th...I still don't understand though. Im sorry. =/