Asked by jena loves culyss
True or False
Triangle DEF has sides measuring 50 cm., 40 cm., and 32 cm. in length. It is a right triangle.
Triangle DEF has sides measuring 50 cm., 40 cm., and 32 cm. in length. It is a right triangle.
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Answered by
GPT-4o mini
To determine if triangle DEF with sides measuring 50 cm, 40 cm, and 32 cm is a right triangle, we can use the Pythagorean theorem. According to this theorem, for a triangle to be a right triangle, the square of the length of the longest side (hypotenuse) should equal the sum of the squares of the other two sides.
Let's denote the sides:
- \( c = 50 \) cm (the longest side)
- \( a = 40 \) cm
- \( b = 32 \) cm
Now, we apply the Pythagorean theorem:
\[
c^2 = a^2 + b^2
\]
Calculating each term:
- \( c^2 = 50^2 = 2500 \)
- \( a^2 = 40^2 = 1600 \)
- \( b^2 = 32^2 = 1024 \)
Now, adding \( a^2 \) and \( b^2 \):
\[
a^2 + b^2 = 1600 + 1024 = 2624
\]
Now we compare:
\[
c^2 (2500) \neq a^2 + b^2 (2624)
\]
Since \( 2500 \) does not equal \( 2624 \), triangle DEF is not a right triangle.
Therefore, the answer is **False**.
Let's denote the sides:
- \( c = 50 \) cm (the longest side)
- \( a = 40 \) cm
- \( b = 32 \) cm
Now, we apply the Pythagorean theorem:
\[
c^2 = a^2 + b^2
\]
Calculating each term:
- \( c^2 = 50^2 = 2500 \)
- \( a^2 = 40^2 = 1600 \)
- \( b^2 = 32^2 = 1024 \)
Now, adding \( a^2 \) and \( b^2 \):
\[
a^2 + b^2 = 1600 + 1024 = 2624
\]
Now we compare:
\[
c^2 (2500) \neq a^2 + b^2 (2624)
\]
Since \( 2500 \) does not equal \( 2624 \), triangle DEF is not a right triangle.
Therefore, the answer is **False**.
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