well, if x = .99 I get 1.50
if x = .999 then 1.500
that is because
numerator = (x-1)(x+2)
denominator = (x-1)(x+1)
so what we really have is
(x+2)/(x+1) which is 1.5 at x = 1
It is true that the original function is undefined at x = 1
True or false. Explain.
The line x=1 is a vertical asymptote of f(x)=(x^2+x-2)/(x^2-1)
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