Tristan is in charge of cheerleading tryouts for their school. They need to pick 12 new cheerleaders to allocate across both the varsity and junior varsity squads. Which of the following is a viable solution?(1 point)

Responses

15 varsity cheerleaders and −3

3
junior varsity cheerleaders
15 varsity cheerleaders and negative 3 junior varsity cheerleaders

8 varsity cheerleaders and 8 junior varsity cheerleaders
8 varsity cheerleaders and 8 junior varsity cheerleaders

8 varsity cheerleaders and 4 junior varsity cheerleaders
8 varsity cheerleaders and 4 junior varsity cheerleaders

0 varsity cheerleaders and 12 junior varsity cheerleaders
0 varsity cheerleaders and 12 junior varsity cheerleaders

1 answer

To determine a viable solution for picking 12 new cheerleaders to allocate across both the varsity and junior varsity squads, we need to ensure that the total number of cheerleaders equals 12 and that there are no negative numbers of cheerleaders.

Let's evaluate each option:

  1. 15 varsity cheerleaders and -3 junior varsity cheerleaders: This option is not viable because it results in a negative count for junior varsity cheerleaders.

  2. 8 varsity cheerleaders and 8 junior varsity cheerleaders: This option sums to 8 + 8 = 16, which exceeds the total of 12.

  3. 8 varsity cheerleaders and 4 junior varsity cheerleaders: This option sums to 8 + 4 = 12, which is a valid solution.

  4. 0 varsity cheerleaders and 12 junior varsity cheerleaders: This option sums to 0 + 12 = 12, which is also a valid solution.

Thus, the viable solutions from the given options are:

  • 8 varsity cheerleaders and 4 junior varsity cheerleaders
  • 0 varsity cheerleaders and 12 junior varsity cheerleaders

Both (3) and (4) present viable solutions, but since typically only one answer would be selected based on the format of the question, the best choice would be:

8 varsity cheerleaders and 4 junior varsity cheerleaders.