Tristan is in charge of cheerleading tryouts for their school. They need to pick 12 new cheerleaders to allocate across both the varsity and junior varsity squads. Which of the following is a viable solution?(1 point)

Question

Responses

8 varsity cheerleaders and 4 junior varsity cheerleaders
8 varsity cheerleaders and 4 junior varsity cheerleaders

0 varsity cheerleaders and 12 junior varsity cheerleaders
0 varsity cheerleaders and 12 junior varsity cheerleaders

15 varsity cheerleaders and −3 junior varsity cheerleaders
15 varsity cheerleaders and negative 3 junior varsity cheerleaders

8 varsity cheerleaders and 8 junior varsity cheerleaders

Answer 1

The viable solution must allocate a total of 12 cheerleaders with non-negative values for both varsity and junior varsity squads.

Let's evaluate the options:

1. 8 varsity cheerleaders and 4 junior varsity cheerleaders: This adds up to 12 (8 + 4) and both values are non-negative. This is a valid solution.

2. 0 varsity cheerleaders and 12 junior varsity cheerleaders: This also adds up to 12 (0 + 12) and both values are non-negative. This is a valid solution.

3. 15 varsity cheerleaders and -3 junior varsity cheerleaders: This does not work because -3 is a negative value. This is not a valid solution.

4. 8 varsity cheerleaders and 8 junior varsity cheerleaders: This adds up to 16 (8 + 8), which exceeds the total of 12. This is not a valid solution.

Therefore, the viable solutions are:

• 8 varsity cheerleaders and 4 junior varsity cheerleaders
• 0 varsity cheerleaders and 12 junior varsity cheerleaders