Janine's speed --- x
Tricia's speed --- x+12
Janince's distance = 20.5(x)
Tricia's distance = 20.5(x+12)
20.5x + 20.5(x+12) = 320
41x + 246 = 320
41x = 74
x = 1.8
So Janine went at 1.8 mph and Tricia went at 13.8 mph ??????
The answers do check out mathematically but don't make a lot of sense.
Tricia and janine are roommates and leave Houston on Interstate 10 at the same time to visit their families for a long weekend. Tricia travels west and Janine travels east. If Tricia's average speed is 12 mph faster than Janine's, find the speed of each if they are 320miles apart in 20 hours and 30 minutes.
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