Triangles Unit Test
11 of 1211 of 12 Items
Question
Use the image to answer the question.
A number line with arrows at both the ends ranges from negative 5 to 5 in unit increments. The number line shows closed points on the following numbers along with letters labeled above the points: A for negative 4, B for negative 1, C for 3, and D for 4.
A triangle has no congruent sides. The lengths of two sides of the triangle are AB and BD . Use the number line above to determine the lengths of AB and BD . Then, use the Triangle Inequality Theorem to determine which two segments have lengths that could be used as the third side of the triangle. Select a response containing 2 possible answers.
(1 point)
Responses
CD and AC
cap c cap d and cap A cap c
AC and BC
cap A cap c and cap b cap c
BC and AD
cap b cap c and cap A cap d
BC and CD
9 answers
Therefore, without knowing the lengths of AB and BD, it is not possible to use the Triangle Inequality Theorem to determine which two segments could be used as the third side of the triangle.
To determine the lengths of AB and BD, we can use the given information from the number line. Since point A is labeled as -4 and point B is labeled as -1, we can determine that AB has a length of 3 units.
Similarly, point B is labeled as -1 and point D is labeled as 4. By subtracting -1 from 4, we can determine that BD has a length of 5 units.
Now, we can use the Triangle Inequality Theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Applying this theorem to the lengths of AB, BD, and AC (labeled as 3 units on the number line), we have 3 + 3 > 5. This inequality is true and satisfies the Triangle Inequality Theorem.
Applying the theorem to the lengths of AB, BD, and CD (labeled as 1 unit on the number line), we have 3 + 1 > 5. This inequality is false and does not satisfy the Triangle Inequality Theorem.
Therefore, the two possible segments that could be used as the third side of the triangle are AC (labeled as 3 units) and BC (not explicitly labeled, but can be determined as the difference between -1 and 3, which is 4 units).
I hope this explanation clarifies the process used to determine the answer.
Based on the given information and the understanding that AB has a length of 3 units and BD has a length of 5 units, I am confident that the two segments that could be used as the third side of the triangle are AC (labeled as 3 units) and BC (not explicitly labeled, but can be determined as the difference between -1 and 3, which is 4 units).
Once again, I apologize for any confusion caused earlier and I appreciate your understanding.