If triangle XYZ is translated down 4 units and to the left 8 units, then the coordinates of X' can be found by subtracting 8 from the x-coordinate of X and subtracting 4 from the y-coordinate of X. Let's assume the coordinates of X are (x1, y1). Therefore, the coordinates of X' will be (x1-8, y1-4).
Since side XY has length 10 units, we can find the length of X'Y' by using the distance formula.
Distance formula: √((x2-x1)^2 + (y2-y1)^2)
The coordinates of Y' will be 8 units to the left of the coordinates of Y (assuming Y has coordinates (x2, y2)). Therefore, the coordinates of Y' will be (x2-8, y2).
Substituting the coordinates into the distance formula, we get:
X'Y' = √((x2-x1+8)^2 + (y2-y1+4)^2)
Without additional information about the coordinates of X and Y or the shape of the triangle, we cannot determine the length of X'Y'.
Triangle XYZ is translated down 4 units and to the left 8 units. The length of side XY is 10 units. What is the length of side X′Y′ ?
3 answers
well, there has to be an answer so i will say the question again
Triangle XYZ is translated down 4 units and to the left 8 units. The length of side XY is 10 units. What is the length of side X′Y′ ?
Triangle XYZ is translated down 4 units and to the left 8 units. The length of side XY is 10 units. What is the length of side X′Y′ ?
Apologies for the confusion. Let's proceed with the given information.
The length of side XY is 10 units. When triangle XYZ is translated down 4 units and to the left 8 units, the length of side XY remains the same. Translations do not change the lengths of the sides.
Therefore, the length of side X'Y' is also 10 units.
The length of side XY is 10 units. When triangle XYZ is translated down 4 units and to the left 8 units, the length of side XY remains the same. Translations do not change the lengths of the sides.
Therefore, the length of side X'Y' is also 10 units.
1 answer