To find the coordinates of the image of triangle XYZ after applying the translation vector \(\langle 3, -4 \rangle\), we will add the components of the translation vector to the coordinates of each point in triangle XYZ.
The given original coordinates are:
- Point X: \((-2, 4)\)
- Point Y: \((-4, 7)\)
- Point Z: \((0, 5)\)
The translation vector is \(\langle 3, -4 \rangle\), which means we will add \(3\) to the \(x\)-coordinate and \(-4\) to the \(y\)-coordinate of each point.
Let's calculate the new coordinates for each point:
-
Translate Point X (-2, 4): \[ X' = (-2 + 3, 4 - 4) = (1, 0) \]
-
Translate Point Y (-4, 7): \[ Y' = (-4 + 3, 7 - 4) = (-1, 3) \]
-
Translate Point Z (0, 5): \[ Z' = (0 + 3, 5 - 4) = (3, 1) \]
Now, we summarize the new coordinates after the translation:
- Image of Point X: \( (1, 0) \)
- Image of Point Y: \( (-1, 3) \)
- Image of Point Z: \( (3, 1) \)
Thus, the coordinates of the image after the translation are:
- \(X' (1, 0)\)
- \(Y' (-1, 3)\)
- \(Z' (3, 1)\)