To translate a point 2 units to the left and 4 units down, we subtract 2 from the x-coordinate and subtract 4 from the y-coordinate.
So the x-coordinate of Y' is 3 - 2 = <<3-2=1>>1.
And the y-coordinate of Y' is -6 - 4 = <<-6-4=-10>>-10.
Therefore, the coordinates of Y' are (1, -10).
Triangle X Y Z is translated 2 units to the left and 4 units down to form triangle X'Y'Z'. If vertex Y is located at (3, -6), what are the coordinates of Y'?
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