Triangle MNO

is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?(1 point)
Responses

(−2,−11)
left parenthesis negative 2 comma negative 11 right parenthesis

(2,−1)
left parenthesis 2 comma negative 1 right parenthesis

(−2,−1)
left parenthesis negative 2 comma negative 1 right parenthesis

(5,−8)

1 answer

To find the coordinates of point \( N' \) after the translation, we start with point \( N(0, -6) \).

The translation involves two operations:

  1. Moving up 5 units, which means we add 5 to the y-coordinate.
  2. Moving left 2 units, which means we subtract 2 from the x-coordinate.

Let's perform the operations step by step:

  1. Moving up 5 units: \[ y' = -6 + 5 = -1 \]

  2. Moving left 2 units: \[ x' = 0 - 2 = -2 \]

So, after the translation, the new coordinates of point \( N' \) are: \[ N' = (-2, -1) \]

Therefore, the correct response is: \[ \text{(−2,−1)} \]