Question

Triangle MNO
is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?(1 point)
Responses

(−2,−11)
left parenthesis negative 2 comma negative 11 right parenthesis

(2,−1)
left parenthesis 2 comma negative 1 right parenthesis

(−2,−1)
left parenthesis negative 2 comma negative 1 right parenthesis

(5,−8)

Answer 1

To find the coordinates of point \( N' \) after the translation, we start with point \( N(0, -6) \).

The translation involves two operations:
1. Moving up 5 units, which means we add 5 to the y-coordinate.
2. Moving left 2 units, which means we subtract 2 from the x-coordinate.

Let's perform the operations step by step:

1. **Moving up 5 units:**
\[
y' = -6 + 5 = -1
\]

2. **Moving left 2 units:**
\[
x' = 0 - 2 = -2
\]

So, after the translation, the new coordinates of point \( N' \) are:
\[
N' = (-2, -1)
\]

Therefore, the correct response is:
\[
\text{(−2,−1)}
\]