Question

Triangle MNO
is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?
(−2,−11)
left parenthesis negative 2 comma negative 11 right parenthesis

(5,−8)
left parenthesis 5 comma negative 8 right parenthesis

(−2,−1)
left parenthesis negative 2 comma negative 1 right parenthesis

(2,−1)

Answer 1

To find the new coordinates of point \( N' \) after translating point \( N \) (which is at (0, -6)) up 5 units and left 2 units, we follow these steps:

1. **Translate up 5 units**: This means we add 5 to the y-coordinate.
\[
-6 + 5 = -1
\]

2. **Translate left 2 units**: This means we subtract 2 from the x-coordinate.
\[
0 - 2 = -2
\]

Now, combining both transformations, the new coordinates \( N' \) are:
\[
N' = (-2, -1)
\]

Thus, the coordinates of \( N' \) are \( (-2, -1) \). Therefore, the correct answer is:
\[
\text{(−2,−1)}
\]