Triangle MNO

Question

is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?
(−2,−11)
left parenthesis negative 2 comma negative 11 right parenthesis

(5,−8)
left parenthesis 5 comma negative 8 right parenthesis

(−2,−1)
left parenthesis negative 2 comma negative 1 right parenthesis

(2,−1)

Answer 1

To find the new coordinates of point \( N' \) after translating point \( N \) (which is at (0, -6)) up 5 units and left 2 units, we follow these steps:

1. Translate up 5 units: This means we add 5 to the y-coordinate. \[ -6 + 5 = -1 \]

2. Translate left 2 units: This means we subtract 2 from the x-coordinate. \[ 0 - 2 = -2 \]

Now, combining both transformations, the new coordinates \( N' \) are: \[ N' = (-2, -1) \]

Thus, the coordinates of \( N' \) are \( (-2, -1) \). Therefore, the correct answer is: \[ \text{(−2,−1)} \]