Let x be the length of side LM.
Then side KL is (3/4)x.
Since we have a 120-degree angle at K, the sum of the other two angles is 180 - 120 = 60 degrees.
Let angle L be y and angle M be z.
Since the sum of the angles in a triangle is 180 degrees, we have
y + z = 60,
y + 120 + z = 180.
Substituting the first equation into the second equation, we get
60 + z = 180,
z = 120.
Since triangle KLM is an isosceles triangle (side KL = side LM), angle L is equal to angle M.
Thus, y = z = 120 degrees.
To find the size of the other two angles of KLM, we need to determine the measures of angles L and M.
Therefore, angle L and angle M are 120 degrees each. Answer: \boxed{120}.
Triangle KLM has a 120-degree angle at K and side KL is three-fourths as long as side LM. To the nearest tenth of a degree, find the sizes of the other two angles of KLM
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