Triangle CDE, with vertices C(-3,-9), D(-2,-2), and E(-8,-5), is drawn inside a rectangle.What is the area, in square units, of triangle CDE?

Answer 1

To find the area of triangle CDE, we can use the formula for the area of a triangle given its vertices:

Area = |(x1(y2-y3) + x2(y3-y1) + x3(y1-y2))/2|

In this case, the vertices of triangle CDE are C(-3,-9), D(-2,-2), and E(-8,-5).

Plugging in the coordinates:

Area = |(-3(-5 - (-2)) + (-2(-9 - (-8)) + (-8(-2 - (-9)))/2|
= |(-3(-3) + (-2(1) + 8(7))/2|
= |(9 - 2 + 56)/2|
= |(63)/2|
= 31.5 square units

Therefore, the area of triangle CDE is 31.5 square units.